1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is todetermine fuel consumption of both cars. Car A travel 2x + 2 miles and Car B travels 3x + 2 miles. Based upon tire wear (x), the cars will use x^2 + x gallons of fuel. What is the totalmileage for both cars? a.) What is the mileage miles/gallons for each car?Car A Car Bb.) What is the total mileage for both cars in simplified form?

Answer:a). Mileage for carA= [tex]\frac{2}{x}[/tex]  , and mileage for carB=[tex]\frac{ 3x+2}{x(x+1)}[/tex]b).total mileage for both is similar to average of them= [tex]\frac{(mileageA + mileageB)}{2}[/tex]=[tex]\frac{5x+4}{2x(x+1)}[tex]mil/gal[/tex]Step-by-step explanation:It is given that the distance traveled by car [tex]A=2x+2=2(x+1)[/tex]And distance traveled by car [tex]B= 3x+2[/tex]We know the mileage is mile/gallon,a).So mileage of car [tex]A= \frac{distance traveled by car A}{gallos of fuel used}[/tex] [tex]=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal[/tex]Similarly , the mileage for car [tex]B= \frac{distance traveled by car A}{gallons of fuel used}[/tex] [tex]=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}[/tex][tex]mil/gal[/tex]b).total mileage for both is similar to average of them= [tex]\frac{(mileageA + mileageB)}{2}[/tex][tex]=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal[/tex]Now divide by 2 for total(average) mileage.[tex]\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal[/tex].Thus those are the answers.