One small piece of ash was ejected from the volcano with an initial velocity of 336ft/sec. The height H, in feet, of the ash projectile is given by the equation: H= -16t^2 + 336t Where t is the time in sec. The graph of this equation will be a parabola. We will assume that the volcano has no height. H= 0 at t= 0. 1. When does the ash projectile reach its maximum height?2.What is its maximum height?3.When does the ash projectile return to the ground?