Which equation, when graphed, has x-intercepts at (-1,0) and (-5,0) and a y-intercept at (0, -30)?f(x) = -6(x + 1)(x + 5)f(x) = -6(x - 1)(x - 5)f(x) = -5(x + 1)(x + 5)f(x) = -5(x - 1)(x – 5)

Answer:f(x) = −6(x+ 1)(x +5) Step-by-step explanation:x-intercepts at (−1, 0) and (−5, 0)so the roots are -1 and -5 (where the graph intersects the x-axis) this will give us that f(x) = (x- root1)(x-root2) = (x- -1)(x- -5) = (x+1)(x+5)y-intercept at (0, −30) is telling us that when x= 0 the y = -30y = a ( x+1)(x+5) , in generaly = a(0+1)(0+5), is the equation if x=0-30 = a·1·5, we need y= -30 when x= 0-30 = 5a , divide both sides of the equation by 5 -6 = a The correct choice is :f(x) = −6(x+ 1)(x +5) f(x) = −6(x − 1)(x − 5)f(x) = −5(x +1)(x +5) f(x) = −5(x − 1)(x − 5).